-16t^2-121t+1=1

Solution for -16t^2-121t+1=1 equation:

-16t^2-121t+1=1

We move all terms to the left:

-16t^2-121t+1-(1)=0

We add all the numbers together, and all the variables

-16t^2-121t=0

a = -16; b = -121; c = 0;
Δ = b2-4ac
Δ = -1212-4·(-16)·0
Δ = 14641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14641}=121$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-121)-121}{2*-16}=\frac{0}{-32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-121)+121}{2*-16}=\frac{242}{-32}
=-7+9/16
$